[問題]答案對嗎??

[bill790602 (REBORN)]

1.the layer of OSI model is responsible for source-to-destination
delivery of an individual packet.
a.presentation b.network c.physical d.session

my answere:c

2.which layer of the OSI model is responcible for source-to-destination
delivery of the entire message?
a.transport b.network c.data-link d.session

Ans:a

3.a queue of characters currently contains:a,b,c,d.d Character d is at the front
t.what would be the contents of the queue after the following operations:
(i)a deletion(ii)the addition of w then of x(iii)a deletions(iiii)
the addition of y
a. a,b,c,w,y b.y,x,c,d c.y,x,w,a,b d.a,b,c,d,w e.c,d,w,x,y


ans:e

另外幾題小弟看不懂?@@麻煩大大們~
為小弟解困^^|||


1.How many 1's are present in the binary representation of 3x512+7x64+5x8+3?
a.8 b.9 c.10 d.11 e.12

2.suppose that fragment of assembly code below is written for an accumulator
-based machine:
LOAD X,MULT Y,STORE T1,MULT T1,STORE T1,LOAD Z,ADD Y,ADD T1,STORE R
what expression evaluated?
a.R=(XY)+Y+Z b.R=(XY)^2+Y+Z c.R=XY^2+Y+Z d.R=XY^2(Y-Z) e.XY^3+Z

3.asssume that a=1 b=2 and c=2 which is evahuated to be true?
a.NOT[(A>1)OR(B=C)] b.NOT(a=1) c.[(a=b)AND(b=c)] d.NOT[(b>a)OR NOT(a<c)]
e.none of the above

4.Big-Endian system,how is a four-byte integer 10A42D stored in memory
from 0 to 3?Draw a figure to illustrate the allocation.

BIG-endian是甚麼?@@書上是不是沒寫???

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※ 發信站: 批踢踢實業坊(ptt.cc) 
◆ From: 122.126.140.201
→ z1x2c3v4:前面三題:B D C
→ z1x2c3v4:Application Presetation Session - Message
→ z1x2c3v4:Transport-segment;Network-packet;DataLink-frame
→ z1x2c3v4:上面是每一層處理的檔案類型..(是這樣說嗎= =?)
→ bill790602:甚麼意思啊?@@
→ bill790602:我好想慘大了= =問題一堆
→ z1x2c3v4:第三題是佇列,有先進先出的特性;abcd,題目說d是頭端
→ z1x2c3v4:(i)從頭端刪除一個(ii)從尾端加上w和x
→ z1x2c3v4:(iii)從頭端刪除一個(iiii)從尾端加上y 所以等於yxwab
→ bill790602:嗯嗯?@@
→ z1x2c3v4:第三題的順序:abcd→abc→xwabc→xwab→yxwab
→ bill790602:嗯嗯
→ bill790602:physical session 是甚麼意思??@@
→ z1x2c3v4:osi模型裡有七層 可以上維基看看
→ bill790602:喔@@拿其他題要怎麼做??.....
→ z1x2c3v4:下面第三題,把數字帶進去,前四個選項算出來都是False
→ bill790602:我只算過二進位的數值耶@@沒算過1和2的???
→ z1x2c3v4:下面第二題-Load X;Mult Y;Sto T1 = T1←X+Y
→ z1x2c3v4:A=1>1是F,B=2=C是T,ForT是F,NotF是T 其他以此類推@@
→ bill790602:原來喔我想太多了= =
→ z1x2c3v4:上面打錯,下面第二題-Load X;Mult Y;Sto T1 = T1←X*Y
→ z1x2c3v4:Mult T1;Sto T1 =T1*T1*T1→(X*Y)(X*Y)
→ z1x2c3v4:Load Z;Add Y;Add T1;Sto R= R←Z+Y+T1 so R=Z+Y+(X*Y)^2
→ z1x2c3v4:load=載入;mult=乘;sto=存回;add=加 這樣懂嗎..
→ bill790602:嗯嗯懂了~原來是這種意思
→ z1x2c3v4:Mult T1;Sto T1 =T1←T1*T1＝(X*Y)(X*Y)
→ z1x2c3v4:God..第二條又打錯..改成上面這條
→ bill790602:恩恩
→ z1x2c3v4:第一題和第四題 小弟表達能力差 不知該如何解釋 抱歉O_Q
→ bill790602:嗯嗯~不過真的謝謝z大那麼詳細的解釋~^^