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The switch S of the circuit shown in the accompanying figure is closed at t=0, at which time C_2 is uncharged and the voltage across C_1 is V. Show that the charge on the capacitors are given by -t/a C_1+C_2 * e q_1(t) = {------------------)C_1 * V C_1+C_2 C_1*C_2*V -t/a q_2(t) = {-----------}(1-e ) C_1+C_2 where a = RC_1*C_2/(C_1+C_2) (17%) R ________ ________ | ^^^^ | | | | | --- C_1 --- C_2 --- --- | | | ╲ | |__________ ╲______| S 題目要證明的是q_1和q_2 標黃色的部分 謝謝摟^^ -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 219.70.170.19