※ 引述《supsymmetry (supsymmetry)》之銘言：
: We know in baseband, signal bandwidth equals (1+r)/2 times signal sampling r
: ate (PAM) or equals (1+r)/2 times signal bit rate (PCM) where r is the raise
: d cosine filter roll-off factor.
: And according to Nyquist sampling theorem, the sampling rate is twice of hig
: hest signal frequency.
: So the bandwidth is (1+r) times the highest signal frequency (PAM).
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因為bandwidth是(1+r)/2*R_s,而R_s=2f_H,所以,bandwidth=(1+r)f_H
: Does this hold for passband?
: It seems as if W=M*R_{s}=M/T_{s} for MFSK where R_{s} is the symbol rate and
: T_{s} is the symbol time duration.
: How about the relationship between highest frequency and bandwidth of passba
: nd signaling? In another word, what's the sampling theorem of passband signa
: ling?
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