推 H45:同一個 port 的 socket bind 只能建立一次 否則失敗。 03/18 17:53
→ zeat:感謝, 問題解決了＝ ＝＋ 03/18 18:04
各位:
我用java內建的DatagramSocket和DatagramPacket寫了個簡單的msger
但遇到些問題.
首先是我用while(true)去監聽receive會出現
java.net.BindException: Address already in use: Cannot bind
這個例外.
另外就是傳送中文字會出現亂碼或是尾巴就不見了O_Q
請問是什麼問題呢?
抱歉, 我找到中文的問題了Orz
中文OK的程式碼:
public static void send(String IP, String msg) {
try {
DatagramSocket socket = new DatagramSocket(1254);
InetAddress ip = InetAddress.getByName(IP);
byte msg_byte[] = msg.getBytes("UTF-8"); //keypoint
DatagramPacket dp = new DatagramPacket(msg_byte, msg_byte
.length, ip, 90);
socket.send(dp);
} catch (Exception e) {
System.out.println("method send occurrence error: " + e);
}
}
public static String receive() {
try{
DatagramSocket socket = new DatagramSocket(90);
byte msg[] = new byte[1026];
String result = "";
DatagramPacket dp = new DatagramPacket(msg, msg.length);
socket.receive(dp);
byte tmp[] = new byte[dp.getLength()];
for (int j = 0; j < tmp.length; j++) {
tmp[j] = dp.getData()[j];
}
System.out.println(new String(tmp, "UTF-8"));
return new String(tmp, "UTF-8");
} catch (Exception e) {
System.out.println("method receive occurrence error: " + e);
return null;
}
}
但是例外我還是不知道啊啊啊Orz
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※ 編輯: zeat 來自: 203.64.129.167 (03/18 16:23)
※ 編輯: zeat 來自: 203.64.129.167 (03/18 16:23)