※ 引述《lovekyoko (我在Tamap 天氣晴)》之銘言：
: Two water pumps, working simultaneously at their respective constant rates,
: took exactly 4 hours to fill a certain swimming pool. If the constant rate
: of one pump was 1.5 times the constant rate of the other, how many hours would
: it have taken the faster pump to fill the pool if it had worked alone at
: its constant rate?
: 答案是 20/3
: 請問這題要怎麼算 謝謝
需要中譯嗎.....
(以下...呃...我意思有到就對了,阿字眼對不對就不知道了XD)
兩個水幫浦,同時各自等速運作,需要四小時才能把一個游泳池灌滿.
如果一台幫浦的速度是另一台幫浦的1.5倍.
試問若用較快的幫浦,需要花多少時間才能將這一個泳池填滿?
令慢者為X 則快者為1.5X
設泳池總水量為L
欲求 : L / 1.5X
L / ( X + 1.5X ) = 4
L = 4 * 2.5X
L = 10X
L / 1.5X = 10X / 1.5X = 20/3
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※ 編輯: newacc 來自: 140.112.240.3 (10/08 00:25)