Re: [問題] 國2幾何

[Albert723 (跛雞)]

設角AED為x
則 角ACB = 〔180 - 50 - (180-2x)〕/2
                  角BAD   角DAE
         = x-25

又 角CDE = 180 - 角ACB - 角CED
         = 180 - (x-25) - (180-x)
         = 25

   得Ans = 25

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