看板 trans_math 關於我們 聯絡資訊
※ 引述《GSXSP (Gloria)》之銘言: : ∫dx/(x^4+1) : 謝謝 1 1 1 S ___________ dx = S ______________________ dx = S _____________________ dx 4 4 2 2 2 2 ( x + 1) ( x +2 x + 1) -2 x ( x^2 +1 ) - 2 x 1 = S ___________________________________ dx (x^2 +1 + 2^0.5 x)(x^2 +1 - 2^0.5 x) A x + B C x+ D = S _______________ dx + S ___________________ dx (x^2 +1 +2^0.5 x) (x^2 +1 - 2^0.5 x 接下來就用Partial Fraction 就可求解..... 2 關鍵在於2x 就可以配出來,個人特稱為"無中生有法"......^^...加油吧... -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.114.212.82
mmmbop:叩首....orz 218.34.226.161 01/06