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※ 引述《anson0810 (奇  )》之銘言: : lim : x->pi/4 (x-pi/4)tan2x : 請問一下這一題的答案是0嗎? 令y=x-pi/4 lim 則原式= y->0 y*tan(2y+pi/2) lim = y->0 y*{-cot(2y)} lim = y->0 -cot(2y)/(1/y) lim = y->0 2(csc2y)^2/(-1/y^2) lim = y->0 (-2)*{y^2/(six2y)^2} lim = y->0 (-2)*(1/4)(2y/six2y)^2 = (-1/2)(1)^2=-1/2 # 參考看看囉~~ -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.124.133.95
Elfiend:原式改寫成(x-π/4)/cot2x再羅必達的算式很簡短220.139.177.197 04/21