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※ 引述《STARS74721 (....)》之銘言: : 1. find the equation of tangent line of f(x) when x = 2 where f(1)=e : and df(x)/dx = 3x^2f(x) df(x) = df(X) ______ 3x^2dx => S _______=S3x^2dx=> ln|f(x)|= x^3+c f(x) f(x) ln|f(x)| x^3+c e = e x^3 c c f(x)= e * e => f(1)= e*e c=0 x^3 f'(x)= e *3x^2 e^8*12(x-2)=(y-e^8) 長的不太像答案的東西 ... -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 192.83.193.6