推 gir147:謝謝^^ 210.85.66.191 07/07
→ gir147:有別的作法?? 210.85.66.191 07/07
推 APOW1204:才兩三部而已差不多八! 61.228.219.74 07/07
→ APOW1204:請指示.. 61.228.219.74 07/07
推 GBRS:首先這個要知道:(a^x)'=a^x*lna 60.198.69.14 07/07
→ GBRS:然後令u=a^x,du=a^x*lna*dx,a^x*dx=(1/lna)du 60.198.69.14 07/07
→ GBRS:算到最後將原假設代回即可... 60.198.69.14 07/07