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※ 引述《mai911345 (mai911345)》之銘言: : sinx : ∫──────── dx : sinx + sin(1-x) sinx sinx ∫──────── dx=∫───────────dx let x-1/2=y sinx + sin(1-x) 2sin(1/2)cos(x-1/2) sin(y+1/2) =∫──────────dy 2sin(1/2)cosy [sinycos(1/2)+cosysin(1/2)] =∫────────────── dy 2sin(1/2)cosy dcosy =-cot(1/2)/2∫────+1/2y cosy =-cot(1/2)/2 ln(cos(x-1/2))+x/2+c -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.112.251.240
ek0519:i服了you~~合差化積也敢考 61.228.25.202 07/10