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※ 引述《boxgene (原來什麼事情都不簡單)》之銘言: : Prove the following statement :Let f be a positive continuous function : on [0 ,1] . Suppose that    :    1 1 : S f(x) dx=a and S f(x^2) dx =b : 0         0       : Then a<2b : ¯ : 請問這要怎麼做 1 1 令x=t^2 a=S 2tf(t^2)dt =2S xf(x^2)dx 0 0 1 1 2b-a=2S f(x^2)dx - 2S xf(x^2)dx 0 0 1 2S (1-x)f(x^2)dx > 0 0 a<2b -- -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 218.34.243.63
boxgene:S(1-x)f(x^2)dx <=怎麼知道他大於零....謝謝 04/12 20:40
pboywc:x在0和1之間 f(x)恆正由題設 04/12 23:28
boxgene:(1-x)不會有影響嗎 04/13 00:54