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※ 引述《vu3cj0su3 ()》之銘言: : Let R be the region bounded by y=x^2 and y=x. : Find the volume of solid that results when R is revolved around : the line y=x : [註 因為還沒學甜甜圈定理及多重積分...so 除了座標軸變換外 可以用 : disk or shell把這題做出來嗎? ] 1 1 1 2 1 1 1 A = ∫ (x-x^2) dx = ∫ x dx - ∫ x dx = --- - --- = --- 0 0 0 2 3 6 1 ∫ x(x-x^2)dx _ 0 1/12 1 x = -------------- = ----- = --- A 1/6 2 1 1 ---∫(x^2-x^4)dx _ 2 0 1/15 2 y = ----------------- = ----- = --- A 1/6 5 |(1/2)-(2/5)| √2 d = --------------- = --- √[(1^2+(-1)^2] 20 1 √2 √2 V = A(2πd) = --- (2π* ---- ) = ----π 6 20 60 -- _ " ~ υ... bliss out out out -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 220.139.244.86
vu3cj0su3:我算的跟你一樣 不過答案是Pi/60 61.230.149.53 12/20 22:47
vu3cj0su3:有可能是答案錯了=.= 61.230.149.53 12/20 22:47
coolbaby119:請問這叫什麼法?x=...y=...d=..看不懂 134.208.34.188 12/23 19:54
coolbaby119:這應該不是殼法或圓盤法吧..不清楚 134.208.34.188 12/23 19:55