[積分] 3題積分

[coolbaby119 (187無聊小豐)]

(1)
      x˙e^(2x)
   ∫ --------- dx
     (2x+1)^2

(2)


   ∫x^3˙sinx  dx

(3)Find the fallacy in the following argument that 0=1

    dv=dx   =>   v=∫dx=x

       1                -1
    u= -    =>    du=  ----  dx
       x               x^2

    0+∫dx= x[x^(-1)]-∫-[x^(-2)]˙x dx  =  1+∫dx

    So,  0=1

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