看板 trans_math 關於我們 聯絡資訊
※ 引述《betray911015 (回頭太難)》之銘言: : 1 1 1 : l i m ---- ( ------ - ---) : x→0^+ √x sinx x 1 1 1 lim --- (------ - ---) x→0+ √x sinx x x - sinx ---------- x‧sinx = lim -------------- x→0+ √x x - sinx = lim -------------- x→0+ sinx‧x^(3/2) L'R 1 - cosx = lim -------------------------------- x→0+ cosx‧x^(3/2) + (3/2)sinx‧√x L'R sinx = lim ------------------------------------- x→0+ -sinx‧x^(3/2) + (3/4)sinx‧x^(-1/2) 1 = lim -------------------------- x→0+ -x^(3/2) + (3/4)x^(-1/2) √x = lim -------------- x→0+ -x^2 + (3/4) = 0 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 218.174.222.247