※ 引述《bitchdog (PEaCE)》之銘言：
: y=[x^3+(5x+1)^6]^4 , find y'
y = (x^3 + (5x + 1)^6)^4
dy
y' = ----
dx
d
= (4)((x^3 + (5x + 1)^6)^3)(----(x^3 + (5x + 1)^6))
dx
= (4)((x^3 + (5x + 1)^6)^3)((3)(x^2) + (6)((5x + 1)^5)(5))
= (4)((x^3 + (5x + 1)^6)^3)((3)(x^2) + (30)((5x + 1)^5))
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