※ 引述《bitchdog (PEaCE)》之銘言：
: let (x^2)y+y-2x-3=0 , find dy |
: --- |
: dx | x=1
(x^2)(y) + y - 2x - 3 = 0
(x^2 + 1)(y) = 2x + 3
2x + 3
y = ---------
x^2 + 1
dy (2)(x^2 + 1) - (2x)(2x + 3)
---- = -----------------------------
dx x^2 + 1
(-2)(x^2) - 6x + 2
= --------------------
x^2 + 1
dy |
---- |
dx |x = 1
-2 - 6 + 2 -6
= ------------ = ---- = -3
1 + 1 2
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