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※ 引述《linda1218 (linda)》之銘言: : sqr2 : S x(sqr(4-x^4))dx =? : 0 aqr2 (1/2)S (sqr(4-x^4))d(x^2) ( set u=x^2 ) 0 2 = (1/2) S sqr(4-u^2) du (set u=2sina, du=2cosada) 0 pi/2 = (1/2) S 4(cosa)^2 da (by wallis formula) 0 = 2 (1/2)(pi/2) = pi/2 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 59.117.76.164
GBRS:如果不背wallis formula就用半角公式代也行.. 211.76.58.233 04/29 20:57