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※ 引述《william01 (小威)》之銘言: : 請問各位大大 小弟有幾題的積分題目 我不會解 可以幫忙解一下嗎? : Find the relative extrema of the function : f(x,y) = 4y^3 + x^2 - 12y^2 - 36y + 2 ? : Find the area of the region completely enclosed by the graphs : of the functions : f(x) = x^3 - 3x + 3 and g(x) = x + 3 ? 令 f(x) = g(x) , 則 x^3 - 3x + 3 = x + 3 x^3 - 4x = 0 => (x)(x^2 - 4) = 0 => (x)(x - 2)(x + 2) = 0 x = -2 , 0 , 2 畫圖可得知當 0 ≦ x ≦ 2 時 , x^3 - 4x ≦ x + 3 -2 ≦ x ≦ 0 時 , x^3 - 4x ≧ x + 3 0 2 因此所求面積 = ∫ (x^3 - 3x) - (x + 3) dx + ∫ (x + 3) - (x^3 - 3x) dx -2 0 0 2 = ∫ x^3 - 4x dx + ∫ 4x - x^3 dx -2 0 x^4 |0 x^4 |2 = --- - (2)(x^2) | + (2)(x^2) - --- | 4 |-2 4 |0 = 4 + 4 = 8 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.119.66.29