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※ 引述《yummy100 (LING)》之銘言: : 拜託~幫忙解答~ : 求 ∫∫∫(x^2 + y^2 + z^2) 所圍體積? R:{ x+y+z=a , x=0, y=0, z=0} : R : Ans: a^5 /20 a a-z a-z-y ∫ ∫ ∫ (x^2 + y^2 + z^2) dxdydz 0 0 0 a a-z =∫ ∫ (1/3)*(a-z-y)^3 + (y^2 +z^2)(a-z-y) dydz 0 0 a =∫ (1/2)*(z^2)*(a-z)^2 + (1/6)*(a-z)^4 dz 0 = (1/2)*[(a^5)/3 - (a^5)/2 + (a^5)/5] - (-1/30)a^5 = (1/60 + 1/30)a^5 = (1/20)a^5 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 118.160.177.227
yummy100:請問第二個積分怎麼積的?140.115.234.121 06/20 00:52
LeoRen:用看的 (-1/12)(a-z-y)^4 + z^2(a-z)y -118.160.177.227 06/20 01:13
LeoRen:(1/2)z^2y^2 + (1/3)(a-z)y^3 - y^4/4118.160.177.227 06/20 01:14
LeoRen:看y積分,不要真的去展開,之後同冪項會簡化118.160.177.227 06/20 01:18