→ Imbufo:z=x^2+y^2代到前面,然後將x跟y以rΘ代換140.138.240.145 06/22 02:15
→ Imbufo:再帶入所求(d=x^2+y^2)中解極值140.138.240.145 06/22 02:15
→ Imbufo:答案是(1/2, 1/2)140.138.240.145 06/22 02:15
→ chat543:這樣還是不知道怎求交點耶~"~125.229.195.125 06/22 02:16
→ chat543:阿勒~球出來是(-1/2,-1/2)125.229.195.125 06/22 02:17
→ Imbufo:那我回一篇@@140.138.240.145 06/22 02:24
→ chat543:我是用求相對極值算的125.229.195.125 06/22 02:25
推 joecheng:用lagrange multiplier應該算的出吧 140.116.110.28 06/22 15:09