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x Let f(x)=∫ e^[(t-1)/t^2] dt, x≧1. Find the interval(s) 1 where f is concave upward, and the interval(s) where f is concave downward. 微了一次還是e...要怎麼解呀= =??? 先感謝各路高手!!! -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 220.132.175.253