→ zptdaniel:降次 123.194.97.168 10/20 00:52
樓上有算出答案？解法是否可提供參考？謝謝^^
※ 編輯: Qmmm 來自: 140.112.128.93 (10/20 01:01)
推 Frobenius:A = √(cos^4(θ)+cos^6(θ)) sec^2(θ) 118.160.213.30 10/20 15:18
→ Frobenius:B = √( 3 + cos(2θ) ) 118.160.213.30 10/20 15:18
→ Frobenius:C = 12 E(θ,1/2) - 4 F(θ,1/2) 118.160.213.30 10/20 15:19
→ Frobenius:E 與 F 各為橢圓函數 118.160.213.30 10/20 15:19
→ Frobenius:y = A [ C + B sin(2θ)] / 6B + const. 118.160.213.30 10/20 15:19
→ zptdaniel:似乎是不能用普通的方法積出來? 123.194.97.168 10/20 15:40
→ a045619891:把cos^4提出來 裡面剩1+cos^2=sin^2 61.31.161.242 10/21 00:42
→ a045619891:開根號後應該就簡單多了 61.31.161.242 10/21 00:43
推 zptdaniel:1-cos^2 = sin^2 (s^2 + c^2 = 1) 123.194.97.168 10/21 00:50
→ Serenede:哪來1+cos^2=sin^2?140.112.250.117 10/21 18:10