[極限]

[bearoct (disparu)]

     lim   θcosθ
  θ→π/2



   有高手可以教一下怎麼解嗎

   謝謝

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推 PaulErdos:直接代入
→ Eliphalet:已知 θ→π/2 , cosθ→ 0 as θ→π/2
→ Eliphalet:所以 θcosθ→π/2*0 = 0 as θ→π/2