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※ 引述《victor7935 (victor)》之銘言: : 1. : Show that : the hyperbola x^2-y^2=5 grad A: 2x i -2y j : and : the ellipse 4x^2+9y^2=72 : are orthogonal. grad B: 8x i + 18y j 二方程式聯立 13x^2 = 117 => x^2 = 9 grad A dot grad B = 16x^2 - 36y^2 = 16x^2 - 36(x^2-5) = -20x^2 + 180 = 0 所以在交會點處orthogonal : 2. : Show that the sum of the x- and y-intercepts of : any line tangent to the graph of : (1/2) (1/2) (1/2) : x + y = c : is constant and equal to c. x, y ≧ 0 graph的grad 1/2√x i + 1/2√y j x/a + y/b = 1 a , b > 0 (a , -b) dot (1/2√x , 1/2√y) = 0 a^2 b^2 ---- = ----- x y 令x = a^2k y = b^2k k > 0 ak + bk = 1 => k = 1 / (a + b) a √k + b √k = √c = √(a + b) => a + b = c const -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 122.124.102.144
shadowlin:請問grad是指切線嗎?那A*B不是有XY項嗎? 122.125.165.33 11/01 15:45
shadowlin:dot又是什麼意思呢?對不起程度不好> < 122.125.165.33 11/01 15:57
shadowlin:為什麼知道要用x/a+y/b=1呢?是怎麼想到? 122.125.165.33 11/01 16:15
shadowlin:和為什麼知道要用(a,-b)去乘? 122.125.165.33 11/01 16:18
Honor1984:dot內積 grad法向量方向導數 垂直切線122.124.102.144 11/01 16:19
Honor1984:x/a + y/b = 1截距式 因為a,b>0所以此切122.124.102.144 11/01 16:20
Honor1984:線之向量平行(a,-b) 為何a,b>0 看grad122.124.102.144 11/01 16:21
shadowlin:謝謝!! 122.125.165.33 11/01 17:07