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1. If f'(X)=0 at x=1,x=2,x=3,then f cannot possibly increase on[0,4]. 這是對的!!...簡單證明 2. Show that cosx < 1 - (1/2)x^2 + (1/24)x^4 for all x >0. 3. Show that the equation P(x)=0 has exactly two real roots, both positive. P(x)= x^4 - 8x^3 + 22x^2 - 24x + 4 4.Prove that a polynomial of degree n has at most n-1 local extreme values. 5.Let f be differentiable on an open interval I.Prove that,if f'(x) = 0 for all x in I,then f is constant on I. 感覺..... 這些問題感覺對大家來說都很簡單!? 有時候都不知道該不該問了= = .... 自己好像還想得不夠多.... -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.123.221.147
Qmmm:第1題敘述是對的~ 140.112.128.93 11/09 19:33
victor7935:= = '我還以為是故意寫這樣的說!!140.123.221.147 11/09 19:45
victor7935:那我修一下好了..140.123.221.147 11/09 19:47
※ 編輯: victor7935 來自: 140.123.221.147 (11/09 19:47)
Qmmm:第2題 令f(t)=cost-1+(1/2)t^2+(1/24)t^4 140.112.128.93 11/09 19:50
Qmmm:由1階導數判別 x=0時為絕對極小值 140.112.128.93 11/09 19:51
Qmmm:sorry 令f(x)=cosx-1+(1/2)x^2+(1/24)x^4 140.112.128.93 11/09 19:51
Qmmm:所以f(x) > 0 for x > 0 ...就證出來了 140.112.128.93 11/09 19:52
Qmmm:第三題一樣是一階導數可以作出來 140.112.128.93 11/09 19:54
※ 編輯: victor7935 來自: 140.123.221.147 (11/09 20:11)
zptdaniel:第一題..隨便抓一個分段定義函數舉反例 123.194.99.216 11/09 20:40
zptdaniel:domf=[0,4] not [1,3] 123.194.99.216 11/09 20:41
zptdaniel:increasing not strictly increasing 123.194.99.216 11/09 20:41
muxiv : 第2題 令f(t)=c http://yofuk.com 04/22 18:01