dy 2 dy
y+ ---- x = sec (xy) (y+ ---- x)
dx dx
dy 2 2
---(x-xsec (xy)) = ysec (xy)-y
dx
2
dy y(sec (xy)-1 ) y
--- = ---------------- = - -----
dx 2 x
-x(sec (xy)-1)
dy
2 ---- x - y
d y dx 2y
---- = - ----------- = ----------
2 x^2 x^2
dx
dy
3 2 ----(x^2) - 2y(2x)
d y dx
----- = ---------------------
3
dx x^4
-2xy -4xy -6y
= ------------- = ----------
x^4 x^3
應該是這樣吧
有錯請指教^^
※ 引述《cloistrevoc (convert)》之銘言：
: xy=tan(xy)
: 1求dy/dx
: 2求d^2y/dx^2
: 3求d^3y/dx^3
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◆ From: 140.113.24.32