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※ 引述《popop922902 ()》之銘言: : 1.FIND the taylor's series at x=0 of the function f(x)=更號(1+X) : 2.lim [更號(4x^2+5x+2) +2x] : x->負無窮大 -------------------------------------------------- ∞ 1.f(x) = Σ (0.5Ck)(x^k) k=0 2. lim {√(4x^2+5x+2)+2x} x->-∞ 5 2 = lim {|x|√(4+ ── + ── ) +2x} x->-∞ x x^2 5 2 = lim {-x√(4+ ── + ── ) +2x} x->-∞ x x^2 2-√(4+ 5/x + 2/(x^2)) = lim ───────────── x->-∞ 1/x = -5/4 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 218.175.77.240
popop922902:第二提的第二步看不懂..210.240.176.170 12/19 23:34
triumph323:同除X阿 但是他是平方所以加絕對值203.121.241.103 12/20 01:52
triumph323:在判別X趨近正還負在判斷203.121.241.103 12/20 01:53
triumph323:不是同除 說錯 應該是把X提出去203.121.241.103 12/20 01:53
kingalan:令x=-t 帶入比較好了解 163.23.231.88 12/20 07:19