推 biggerlin:感謝! 61.228.197.93 01/02 22:54
※ 編輯: chanchiu5566 來自: 61.217.194.223 (01/02 22:58)
※ 引述《biggerlin (比格)》之銘言：
: 1
: (a)∫───────dx
: √[x+x^(3/2)]
x+x^(3/2) = x[1 + x^(1/2)]
令u = 1 + x^(1/2)
=> x = (u-1)^2 dx = 2(u-1)du
2(u-1)du
=> ∫─────── = 4√u + c
(u-1)√u
最後一式分母寫錯 小改一下
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