推 zxc321:請問第二題算到∫1+sinx/cosx^2 要怎麼算? 59.127.194.112 03/06 23:19
→ zxc321:第二題的答案是 tanx+secx+c 謝謝~~ 59.127.194.112 03/06 23:19
→ linch1:(1-sinx)/cosx^2 = sec^2+secxtanx 122.118.2.14 03/06 23:46
→ linch1:(1-sinx)/cosx^2 = sec^2-secxtanx 122.118.2.14 03/06 23:48
→ linch1:答案應該是 tanx-secx+C 吧 122.118.2.14 03/06 23:49
推 zxc321:不好意思答案說錯 若有帶區間[0,π/4] 59.127.194.112 03/06 23:50
→ zxc321:的話 第二題答案是 2-√2 59.127.194.112 03/06 23:50
→ linch1:第二題應該算到∫1-sinx/cosx^2 dx 122.118.2.14 03/06 23:50
→ zxc321:我題目看成積分 1/1-sinx dx 59.127.194.112 03/06 23:51
→ linch1:把tanx-secx代區間[0,π/4]會得到2-√2 122.118.2.14 03/06 23:51
→ zxc321:了解了 謝謝你 ~~ 59.127.194.112 03/06 23:52
→ linch1:不客氣 122.118.2.14 03/06 23:52