看板 trans_math 關於我們 聯絡資訊
※ 引述《bbb286bp6 (bbb286bp6)》之銘言: : 6.A manufacturer of digital clocks determines that he can sell x clocks per : week at price p where x and p are related by the equation : x^2+3xp+p^2=4400. : This equation determines demand as a function of price,x=Q(p), near the : point (p.,x.)=(40,20) ---("."為下標0) : (a) If price is increasing at the rate of 50% per week how fast is demand : changing when p=$40? : (b) Find dx/dp at the point (p.,x.)=(40,20) (a) 令p=at => dp/dt= a = 0.5 (依題目敘述) 2 2 2 2 2 x +3xp+p = 4400 => x +3xat+a t = 4400 (將a帶入和對t微分) => 2x(dx/dt) + 3/2t(dx/dt) + 3/2x + 1/2t = 0 => dx/dt = (3/2x+1/2t) / (-2x-3/2t) => = (3/2x+ p ) / (-2x-3p ) 帶入(p,x)=(40,20) => = - 7/16 # 2 2 (b) x +3xp +p =4400 => 2x(dx/dp) + 3p(dx/dp) + 3x + 2p = 0 => dx/dp = - (3x+2p)/(2x+3p) 帶入(40,20) = - 7/8 # (有錯請不吝指正) -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 219.84.254.166