推 di7101483:不過方程式有根號耶！ 這樣要怎麼解 140.127.64.27 12/06 17:26
※ 引述《di7101483 (新生代)》之銘言：
: Find the points on the graph of y=x^5/3+x^1/3 at which the tangent line is
: perpendicular to the line 2y+x=7
: 這題的方程式怎麼那麼難解
y' = (5/3)x^4 + (1/3)x^(-2/3)
2y+x=7 斜率 -1/2
所以找出使得y' = 2的點即為所求
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