看板 trans_math 關於我們 聯絡資訊
※ 引述《kylestyle (最近有點煩)》之銘言: : Find the average value of f(x,y) = xy over the quarter circle : x^2 + y^2 ≦ 1 in the first quadrant : 求板上大大解答 By definition, the average value is given by _ 1 f = -----∫∫f(x,y)dA A(Ω) Ω where Ω = {(x,y) | x^2+y^2≦1, x≧0, y≧0} and A(Ω) denotes the area of Ω. Thus _ 4 1 π/2 f = --- ∫∫r^2 cosθsinθ r dθ dr π 0 0 4 r^4|1 cos 2θ |π/2 = --- ---| (- --------)| π 4 |0 4 |0 = 1/2π 有錯請指正 m(_ _)m -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 59.115.146.209
kylestyle:感謝大大 突然覺得這題頗簡單 = =125.228.152.142 06/24 18:36
kylestyle:有一點搞不清楚 xy在換成極式相乘後125.228.152.142 06/24 18:41
kylestyle:等於r^2 cosθsinθ r125.228.152.142 06/24 18:42
kylestyle:這後面多出來的r是怎麼來的125.228.152.142 06/24 18:42
suhorng:dx dy = dA = r dr dθ 59.115.146.209 06/24 18:45
suhorng:recall that dxdy=|∂(x,y)/∂(u,v)|dudv 59.115.146.209 06/24 18:46
kylestyle:多謝指點 全然懂了125.228.152.142 06/24 18:51