→ explore:令arctanx=u [1/(1+x^2)]dx=du111.255.170.105 12/03 00:58
→ explore:cosu=1/[(1+x^2)^(1/2)]111.255.170.105 12/03 00:59
→ explore:原式得ucosu 再用分部積分 然後換回x111.255.170.105 12/03 01:01
→ PS3bluray:感謝 我試試看 58.114.103.18 12/03 13:22
→ PS3bluray:忘記回來推文 有求出來了 謝謝一樓 58.114.103.18 12/06 16:18