→ yhliu:lim (1+1/2+...+1/n-ln(n)) = (Euler's γ)111.252.124.143 05/28 11:43
pn qn
lim (Σ 1/k - Σ 1/k)
n→∞ k=1 k=1
pn
= lim Σ 1/k (r is euler constant)
n→∞ qn+1
(1+ 1/2 +.....+1/n) r + ln(n) L
lim --------------------- = lim -------------- = 0
n n
(1+ 1/2 + ....+1/2n) r + ln(2n) L
lim --------------------- = lim -------------- = 0
n n
(1+ 1/2 +.....+1/n) r + ln(n) L
lim --------------------- = lim -------------- = 1
ln(n) ln(n)
我看不懂上面三行是怎來的 請幫我解釋
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