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各位大大安安 想請問一個題目 find the distance from the point(2,1,3) to the line x-1/2 = y/-1= z+1/1. 我的作法是: 將x-1/2 = y/-1= z+1/1 寫成2x-y+z-1=0 (2,1,3)代入,答案為(5/6)^0.5 但是正確答案不是這個,想問我是哪邊出錯了? -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.124.141.113
BaBi:我還滿好奇你怎麼化出2x-y+z-1=0的... 114.41.133.189 05/29 00:24
BaBi:不是先依參數條件設垂點嗎... 114.41.133.189 05/29 00:26
BaBi:利用最近時兩線向量垂直, dot = 0 解參數 114.41.133.189 05/29 00:27
BaBi:然後帶回得垂點, 距離就出來了啊... 114.41.133.189 05/29 00:27
winter5690:我照babi大的方法做,但答案還是不對140.124.141.113 05/29 00:35
winter5690:是我計算錯了嗎?babi你算是多少?140.124.141.113 05/29 00:35
winter5690:ans is (83/3)^0.5140.124.141.113 05/29 00:36
winter5690:更正不是3是6140.124.141.113 05/29 00:36