推 iamphilip526:謝謝BaBi大..效率超高!!! 61.58.173.170 07/19 23:01
修正下筆誤
※ 編輯: BaBi 來自: 36.234.224.120 (07/21 19:35)
※ 引述《iamphilip526 (Philip)》之銘言：
: Find the equation of the tangent line for the curve represented by x = √t and
: y= (1/2) t^2 at the point where t=4 .
: 在此先謝謝各位大大了 ><
dy | dy/dt | t |
---- | = ------- | = -------------- | = 16
dx |t=4 dx/dt |t=4 1/[2sqrt(t)] |
|
(x,y)| = (2,8)
|t=4
Equation of the tangent line
(y-8) = 16(x-2)
=> 16x-y = 24
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