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※ 引述《iamphilip526 (Philip)》之銘言: : Find the gradient of f(x,y) = ln(x^2 + y^2 + 1) + e^2xy at the point (0,-2) : 不好意思~ 又要麻煩各位大大了 QQ 2x 2y | [ -------------- + (2y)e^(2xy) ] + [ -------------- + (2x)e^(2xy) ]| x^2 + y^2 +1 x^2 + y^2 +1 |(0,-2) = [ (0) + (-4) ] + [ (-4/5) + (0) ] = -24/5 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 36.234.226.221
iamphilip526:感恩!! 61.58.173.170 07/19 23:25