→ keith291 :(a)反了 x-->0+, mx=0,m=任意數 x-->0- sinx=0 04/22 23:18
→ keith291 :然後因左極限=右極限,故極限存在,又極限值=函數值 04/22 23:20
→ keith291 :故連續 04/22 23:20
→ keith291 :(b)類似 用定義做 不能直接微 04/22 23:23
→ elecsheep224:謝謝你！ 04/22 23:44
題目:
Let sinx , x<=0
mx , x>0
(a)Find values of the constant m such that f(x) is continuous at x=0
(b)Find values of the constant m such that f(x) is differentiable at x=0
(a)
x-->0+ , sinx=0
x-->0- , m*0=0,m=任意數
(b)
sinx跟mx都微分
x--->0 cosx=m, m=1
是否能這樣解？
煩請各位幫忙，謝謝！
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