[計量] OG的168與175題

[angie0716 (大寶與困寶)]

題目是這樣的

168.An airline passenger is planning a trip that involves three connecting

flights that leaves from Airports A, B, and C,respectively. The first flight

leaves Airport A every hour, beginning at 8:00 a.m., and arrives at Airport

B 2 and 1/2 hours later. The second flight leaves Airport B every 20 minutes,

beginning at 8:00 a.m., and arrives at Airport C 1 and 1/6 hours later. The

third flight leaves Airport C every hour, beginning at 8:45 a.m. What is the

least total amount of time tha passenger must spend between flights if all

flights keep to theur schedules?                         Ans:1 hr 15 minutes

這題其實題目有點看不太懂..外加解答看的霧煞煞..


另一題175.

A square countertop has a square tile inlay in the center, leaving an untiles

strip of uniform width around the tile. If the ratio of the tiled area to the

untiled area is 25 to 39, which of the following could be the width, in inches

, of the strip?
                                                         Ans:1.3.4

這題也是題目看不太懂@@....麻煩大家了
謝謝:)

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推 seawolfssn:168. A->B->C 三段航程聯票 就是A出發到B B出發到C
→ seawolfssn:請問旅客所花費的"候機"時間?
→ seawolfssn:航站A 每小時一班飛機飛B
→ seawolfssn:航站B 每20分鐘一班飛機飛C
→ seawolfssn:假設蝙蝠俠 在航站A搭乘早上8:00AM經過2 1/2小時到航B
→ seawolfssn:他到達航站B 時間為10:30 所以蝙蝠俠比須等待 10分鐘
→ seawolfssn:搭乘10:40的飛機到航站C
→ seawolfssn:蝙蝠俠花了1 1/6到達航站C 到達航站C時間為11:50
→ seawolfssn:               小時
→ seawolfssn:然後蝙蝠俠必須等12:45離開C航廈的班機
→ seawolfssn:因為C航站從 8:45起 每一小時發一班飛機
→ seawolfssn:所以蝙蝠俠必須等待 55分鐘的候機時間~
→ seawolfssn:所以 10 + 55 = 65 = 1 hour 5 minutes
→ seawolfssn:*補充* A->B->C 三段航程聯票=A到B B到C C再到某地!