精華區beta Math 關於我們 聯絡資訊
Let L_k(λ) be the polynomial in λ of degree n-1 defined by the eq n λ-λ_j L_k(λ) = Π (---------) where λ_1,λ_2,...,λ_n are n distinct scalars. j=1 λ_k-λ_j j≠k (a) Prove that 0 if λ_i≠λ_k L_k(λ_i)={1 if λ_i =λ_k (b) Let y_1,...,y_n be n arbitrary scalars, and let n p(λ) = Σ y_kL_k(λ) k=1 Prove that p(λ) is the only polynomial of degree ≦ n-1 which satisfies the n equations p(λ_k)=y_k for k=1,2,....,n. n (c) Prove that Σ L_k(λ)=1 for every λ, and deduce that for every square k=1 n matrix A we have Σ L_k(A)=I, where I is the identity martix and k=1 n A - λ_jI L_k(A)=Π(-----------) for k=1,2,....,n. j=1 λ_k - λ_j j≠k -- 小武的照片 歡迎來我的相本晃晃喔 ^_^ http://tinyurl.com/d289a 拍的不好請多包含 ^^" -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 218.169.11.178