精華區beta Math 關於我們 聯絡資訊
※ 引述《PttFund (批踢踢基金)》之銘言: : A metric space M is said to be locally path-connected if : each point in M has a neighborhood U is path-connected. : Show that (M is connected and locally path-connected) : iff (M is path-connected). Note: 在高微課中, path-connected ===> connected 是已經知道的事實, 而我們也曉得 connected =X=> path-connected, 反例是 cl(S), where S = { x╳sin(1/x) | 0 < x≦1 }. Sketck of proof: 1. Define a relation on M by saying x~y iff there is a path from x to y. Show that this is an equivalent relation. The equivalence classes are called the path components of M. Clearly, M is path-connected iff M has exactly one path component. 2. Show that M is locally path-connected => each path component of M is open. 3. Deduce that a connected and locally path-connected space is connected. 先提示到這邊. -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.112.218.142
iddee:這題哪一本高微書上的阿 好陌生的題目 證明也不短 61.219.178.213 07/16
PttFund:不曉得 XD140.112.218.142 07/16