[分析] 一題高微

[hanabiz (叛逆之臣也)]

a_1 >= 0, a_2 >= 0, a_(n+2) = [ a_n * a_(n+1) ]^(1/2), for all n >= 1,

L = [ a_1 * (a_2)^2 ]^(1/3)

Show that {a_n} has the limit L indicated.

thx

--
※ 發信站: 批踢踢實業坊(ptt.cc) 
◆ From: 61.224.103.238
推 asynchronous: _s_n =  log(a_n / a_1) 是等比級數