精華區beta Math 關於我們 聯絡資訊
If X is an infinite set, then A = { E 屬於 X | E is cofinite } is an algebra but not σ-algebra on X 舉例: ∵ Any infinite set contains a countable infinite set. Now, X is an infinite set, we can choose a countable infinite subset A = { x_1, x_2, ... ...} x_1 屬於 X , x_2 屬於 X-{ x_1} , x_3屬於 X-{ x_1, x_2},...以此類推... Let E = { x_2,x_4,....} = {x_2n | n=1,2,...} A_n = { x_2n}, n = 1,2,... ∞ _ But ∪ A_n = E 不屬於 A (∵ E is not finite 且 E is not finite) n=1 看不懂黃色這個例子...可不可以講解一下..謝謝...^^ -- -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 58.114.225.200 ※ 編輯: ericakk 來自: 58.114.225.200 (04/02 13:23) ※ 編輯: ericakk 來自: 58.114.225.200 (04/02 13:23)
FANggot :例子講的似乎是 A is not closed with respect to 04/02 14:19
FANggot :countable union. 04/02 14:20
mathblue :σ-algebra是coutable union之後都要原空間裡 04/02 15:38