精華區beta Math 關於我們 聯絡資訊
※ 引述《Rudin5566 (魯丁.嗚嗚溜溜)》之銘言: : If 1.f is continuous on [a b] : 2.F(x)=supf([a x]) : Prove that F is continuous on [a b] Since f is continuous on compact set [a,b], f is uniformly continuous on [a,b]. Given ε>0 there is a δ>0 such that |f(x)-f(y)|<ε whenever 0<|x-y|<δ. WLOG assume y>x. For 0<|y-x|<δ, sup f([a,y]) = sup{ sup f([a,x]) , sup f([x,y]) }. If sup f([a,y]) = sup f([a,x]), then F(y)-F(x)=0<ε. If sup f([a,y]) = sup f([x,y]). Since f is continuous on [x,y], then there exists y' in [x,y] such that sup f([x,y]) = f(y'). ε > f(y') - f(x) ≧ f(y') - sup f([a,x]) = F(y) - F(x) ≧ 0 > -ε Thus |F(y)-F(x)|<ε whenever 0<|x-y|<δ □ -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 118.168.166.97 ※ 編輯: Math 來自: 118.168.166.97 (11/16 04:08)
ic6413 :Math 還是比 Rudin 厲害XD 11/16 19:05