精華區beta Math 關於我們 聯絡資訊
第一題已經有人做了 提供第二題一些想法 因為 1 + x^2 + xy + y^2 = 1 + 3/4 x^2 + (y+x/2)^2 所以所有的解都是嚴格遞增且 |y(x)-y(0)| < M for all x 有了 sup_n ∣f_n(1/n)∣<∞ 當然就有 sup_n {sup |f_n(x)|} 且每個f_n都是嚴格遞增這樣的條件 這樣當然可以找到一組Subsequence Converge to some f 接下來的證明就都很直接明瞭了 ※ 引述《gok338 (HuaHua)》之銘言: : 1.試判斷正確性,並證明 : There exists no function U(x,y) which is C^2 in R^2 and satisfies : U(x,y) = 0 on x^2 + xy + y^2 =1, U(x,y)≧0 and Uxx + Uyy = 1+U^2 : for x^2 + xy +y^2<1. : 還有C^2 in R^2 是什麼意思?? 謝謝~ : 2.Assume that f_n: R→R (n=0.1.2...) is a sequence of differentiable : functions s.t each f_n(x) is a solution of the equation : y'(1 + x^2 + xy + y^2) = 1. If sup_n ∣f_n(1/n)∣<∞, : prove that there exists a subsequence f_n_k(x) s.t : lim f_n_k(x) = f(x) exists for x in R. : k→∞ : This limit f(x) must also be a solution of y'(1 + x^2 + xy + y^2) = 1. : 謝謝~ -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 128.32.228.171