精華區beta Math 關於我們 聯絡資訊
※ 引述《zxc95 ()》之銘言: : Compute ∫F dx for the following F and C : : c 改這樣好了 ∫F dX X代表向量 : (a) F(x,y,z)=(yz,x^2,xz); C is the line seqment from (0,0,0) to (1,1,1). X=(t,t,t) 0 <= t <= 1 dX = (1,1,1)dt 原式 = ∫(t^2,t^2,t^2) (1,1,1) dt t屬於[0,1] 內積 : (b) F is as in (a); C is the portion of the curve y=x^2 , : z=x^3 from (0,0,0) to (1,1,1). X = (t,t^2,t^3) 0 <= t <= 1 dX = (1,2t,3t^2)dt 原式 = ∫(t^5,t^2,t^4) (1,2t,3t^2) dt t屬於[0,1] 內積 : 答案:(a) 1 (b) 23/21 : 跟我算的不一樣,想請教高手!! : 謝謝~ -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.112.66.53
zxc95 :謝謝你:) 04/18 19:27