精華區beta Math 關於我們 聯絡資訊
※ 引述《Helilo (哈里路)》之銘言: : Prove the following function is integrable : f(x) = 0 , x is not a rational number : 1/q , x = p/q , p,q belong to N, (p,q) = 1 以下根據math1209大大給的提示嘗試作答 為求題目完整先定義 f(0) = 1, 定義 x belongs to [0,1] Proof: Because irrational numbers are dense For any partition P={x_1,x_2,....,x_n} We can find a irrational number x with x_(i-1) <= x <= x_i for any i => m_i = inf{f(x)|x_(i-1) <= x <= x_i} = 0 => L(P,f)=0 For any ε> 0, exist n > 3/(2ε) For the fixed n, there are only n(n-1)/2 + 2 of rational numbers p/q such that 1/q >= 1/n. Let P be a partition of [0,1] such that Δx_i < 1/n^3 for all i => U(P,f) < (n(n-1)/2+2)*1/n^3 + 1/n < 3/(2n) for n large enough => U(P,f) < 3/(2n) < ε => U(P,f) - L(P,f) < ε => f is integrable. 這個證明不知道對不對@@" 而且有點偷懶 要是區間是[a,b]而非[0,1]的話又要重寫了orz 懇請各位賜教<(_ _)> -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 99.135.74.143
math1209 :yes. 12/11 14:21
math1209 :你觀念上是對的, 這樣就行了. 12/11 14:22
Helilo :感謝<(_ _)> 12/11 14:35