作者Helilo (哈里路)
看板Math
標題Re: [微積] 高微的積分問題
時間Fri Dec 11 13:53:38 2009
※ 引述《Helilo (哈里路)》之銘言:
: Prove the following function is integrable
: f(x) = 0 , x is not a rational number
: 1/q , x = p/q , p,q belong to N, (p,q) = 1
以下根據math1209大大給的提示嘗試作答
為求題目完整先定義 f(0) = 1, 定義 x belongs to [0,1]
Proof:
Because irrational numbers are dense
For any partition P={x_1,x_2,....,x_n}
We can find a irrational number x with x_(i-1) <= x <= x_i for any i
=> m_i = inf{f(x)|x_(i-1) <= x <= x_i} = 0
=> L(P,f)=0
For any ε> 0, exist n > 3/(2ε)
For the fixed n, there are only n(n-1)/2 + 2 of rational numbers p/q
such that 1/q >= 1/n. Let P be a partition of [0,1] such that
Δx_i < 1/n^3 for all i
=> U(P,f) < (n(n-1)/2+2)*1/n^3 + 1/n < 3/(2n) for n large enough
=> U(P,f) < 3/(2n) < ε
=> U(P,f) - L(P,f) < ε
=> f is integrable.
這個證明不知道對不對@@"
而且有點偷懶
要是區間是[a,b]而非[0,1]的話又要重寫了orz
懇請各位賜教<(_ _)>
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◆ From: 99.135.74.143
推 math1209 :yes. 12/11 14:21
→ math1209 :你觀念上是對的, 這樣就行了. 12/11 14:22
→ Helilo :感謝<(_ _)> 12/11 14:35