課程名稱︰質能平衡甲
課程性質︰系定必修
課程教師︰諶玉真
開課系所︰化學工程學系
考試時間︰忘了，但不會晚於2006/03/27
是否需發放獎勵金：乘以八就好，謝謝^^
（如未明確表示，則不予發放）
試題 :
1. An open-end mercury manometer is connected to a low-pressure pipeline that
supplies a gas to a laboratory. Because paint was spilled on the arm connected
to the line during a laboratory renovation, it is impossible to see the level
of the manometer fluid in this arm. During a period when the gas supply is
connected to the line but there is no gas flow, a Bourdon gauge connected to
the line downstream from the manometer gives a reading of 7.5 psig. The level
of mercury in the open arm is 900 mm above the lowest part of the manometer.
(a) When the gas is not flowing, the pressure is the same everywhere in the
pipe. How high above the bottom of the manometer would the mercury be in the
arm connected to the pipe?
(b) When gas is flowing, the mercury level in the visible arm drops by 25 mm.
What is the gas pressure (psig) at this moment?
2. State what you would plot to get a straight line if experimental (x,y) data
are to be correlated by the following relations, and what the slopes and
intercepts would be in terms of the relation parameters.
(a) y^2 = a*e^(-b/x)
(b) y^2 = m*x^3 - n
(c) 1/ln(y-3) = (1+a*√x)/b
(d) (y+1)^2 = [a*(x-3)^3]^-1
(e) y = exp(a*√x + b)
(f) xy = 10^ [a(x^2+y^2)+b]
(g) y = [ax + b/x]^ -1
3. A seed crystal of diameter D (mm) is placed in a solution of dissolved salt,
and new crystals are observed to nucleate (form) at a constant rate r
(crystals/min). Experiments with seed crystals of different sizes show that the
rate of nucleation varies with the seed crystal diameter as
r (crystals/min) = 200D - 10D^2 (D in mm)
(a) What are the units of the constants 200 and 10?
(b) Calculate the crystal nucleation rate in crystals/s corresponding to a
crystal diameter of 0.050 inch.
(c) Derive a formula for r (crystals/s) in terms of D(inches). Check the
formula using the result of part(b).
4.The heat capacity of ammonia, defined as the amount of heat required to raise
the temperature of a unit mass of ammonia by precisely 1° at a constant
pressure, is, over a limited temperature range, given by the expression
Cp[Btu/lbm*°F] = 0.487 + 2.29* 10^ -4 T (°F)
Determine the expression for Cp in J(g°C) in terms of T(°C).
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