精華區beta NTU-Exam 關於我們 聯絡資訊
課程名稱︰ 分析化學乙上 課程性質︰ 課程教師︰ 何國榮 開課學院: 理學院 開課系所︰ 化學系 考試日期(年月日)︰ 2008/1/16 考試時限(分鐘): 10:20-12:10 是否需發放獎勵金: 是 (如未明確表示,則不予發放) 試題 : Briefly answer the following questions. 1. For a sparingly soluble salt, explain that the activity decreased when the increased of ionic strength. 5% 2. For a diprotic acid H2A, please (a) derive the equation for the calculation of [H+] (b) show that ignoring the concentration of water and the second dissociation, the equation can be simplified to [H+]=√Ka[H2A]. (c) show that under the condition Ka/C < 2.5x10^-3, the equation can be simplified to √KaC. 12% 3. Explain that the isoionic point is very close to the isoelectric point. 5% 4. Explain how isoelectric focusing works. 5% 5. For a buffer solution, describe the major factors to the buffer capacity. 6% 6. Explain the sodium error and its effect to pH measurement. 6% 7. Even if two solutions have the same concentration of [H+], using the same pH meter, the pH value may not be the same. Why? 5% 8. (a) Explain the purpose of using auxiliary complexing agents in EDTA titration. 4% (b) Explain that multidentate instead of monodentate ligand is used in metal ion titration. 4% 9. Explain that the standard reduction potential of AgCl + e- → Ag + Cl- is smaller than the standard reduction potential of Ag+ + e- → Ag. 5% 10. (a) Describe the method of iodometry. 4% (b) Describe the procedure to detect the end point. 4% 11. (a) 0.010 M HCl, (b) 0.010 M HA with pKa=4, (c) 0.00010 M HCl solutions are titrated with NaOH, please draw the three titration curve in the same diagram. 9% 12. (a) 0.0500 M Fe2+, (b) 0.00050 M Fe2+ solutions were titrated with Ce4+, please draw the two titration curve in the same diagram. 6% Fe3+ + e- → Fe2+ E°=0.767 V Ce4+ + e- → Ce3+ E°=1.70 V 13. A potentiometer consists of a Pt and a Calomel electrode is used in the oxidation titration of Fe2+, write down the two half cell reactions. 5% 14. Explain that mercury is a popular material for the study of reduction reaction. 5% 15. Explain that voltammetry is performed under complete concentration polarization condition. 5% 16. A nickel-metal hydride rechargeable battery for laptop computers is based on the following chemistry: discharged Cathode: NiOOH(s) + H2O + e- ────→ Ni(OH)2(s) + OH- discharged Anode: MH(s) + OH- ────→ M(s) + H2O + e- The anode material, MH, is a transition metal hydride or rare earth alloy hydride. Explain why the voltage remains nearly constant during the entire discharge cycle. 5% -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.112.250.149
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